I have a few questions / puzzles from a popular pocket encyclopaedia from 1888 which you may like to try...

1) Divide 2 by 5 so the result will be 1000

2) Place 15 sheep in 4 pens so that there will be the same number of sheep in each pen

3) Arrange 5 numbers, none of which are greater than 10, so that when read from left to right, the one on the right will always be nearer to 10

than the preceding one, and the first number will be nearer 10 than the

5th

4) A lady sent a diamond cross to a jeweller to be repaired. She noted

that the number of diamonds, counting from the bottom of the cross to

the top, or from the bottom to the end of each cross piece , was 9. The

jeweller retained 2 diamonds, but the number counted in the same manner

was still 9. How?

I've re-phrased the next one as the answer was in the question.

5) A man rides into town and finds 3 brothers in a bit of a quandary.

Their father had died and left 17 horses to be shared amongst them. To

the eldest he leaves 1/2 his horses, to the next 1/3, and to the last

1/9. The man resolves the issue to everyone's satisfaction without

sacrificing a horse. How?

Good Luck!

1) Divide 2 by 5 so the result will be 1000

2) Place 15 sheep in 4 pens so that there will be the same number of sheep in each pen

3) Arrange 5 numbers, none of which are greater than 10, so that when read from left to right, the one on the right will always be nearer to 10

than the preceding one, and the first number will be nearer 10 than the

5th

4) A lady sent a diamond cross to a jeweller to be repaired. She noted

that the number of diamonds, counting from the bottom of the cross to

the top, or from the bottom to the end of each cross piece , was 9. The

jeweller retained 2 diamonds, but the number counted in the same manner

was still 9. How?

I've re-phrased the next one as the answer was in the question.

5) A man rides into town and finds 3 brothers in a bit of a quandary.

Their father had died and left 17 horses to be shared amongst them. To

the eldest he leaves 1/2 his horses, to the next 1/3, and to the last

1/9. The man resolves the issue to everyone's satisfaction without

sacrificing a horse. How?

Good Luck!

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